tag:blogger.com,1999:blog-12604614.post115707708692550304..comments2023-06-12T05:26:38.585-07:00Comments on Math Refresher: sin x Larry Freemanhttp://www.blogger.com/profile/06906614246430481533noreply@blogger.comBlogger3125tag:blogger.com,1999:blog-12604614.post-19230574174884892202012-12-19T04:14:48.686-08:002012-12-19T04:14:48.686-08:00Very beautiful proof! Thank you very much for post...Very beautiful proof! Thank you very much for posting it and explaining it with so many details!!!SkullDemonhttps://www.blogger.com/profile/13576808462369517211noreply@blogger.comtag:blogger.com,1999:blog-12604614.post-38120949520551636152009-07-02T05:39:37.511-07:002009-07-02T05:39:37.511-07:00Thanks for your effort.
This is what I had tried...Thanks for your effort. <br /><br />This is what I had tried before landing at your blog.<br /><br />Area of triangle OCD is less than the sector's area<br /><br />=> (1/2)*sin x *cos x <(1/2)*x<br /><br />And then I was stuck... <br /><br />I thought that the inequality could be written as<br /><br />sin(2x) < (2x), 0< (2x) < (pi/2)<br /><br />Assuming y = 2x, <br /><br />sin y < y, 0< y < (pi/2)<br /><br />Is this a valid proof? Or am I kidding myself?<br /><br />Thanks for your timeAnonymousnoreply@blogger.comtag:blogger.com,1999:blog-12604614.post-52987974573272448332009-06-30T17:54:32.845-07:002009-06-30T17:54:32.845-07:00Thanks for the lesson. It helped me understand the...Thanks for the lesson. It helped me understand the squeezing theorem in my Calculus book.<br /><br />UNC Greensboro StudentAnonymousnoreply@blogger.com